Using the multimeters, determine the actual resistance of each of the five resistors and the EMF of the two batteries. Use these values in all subsequent calculations. EMF 1 = 1. 4689 EMF 2 = 1. 4806 R100 = 9 9 . 38 R 330 = 325 . 5 R560 = 555 . 8 R1000 = 1004. 5 R1500 = 1476 PART A Construct the circuit below using one of the batteries and the resistors. You must get the instructor's approval that the circuit is correct before continuing. Measure the voltage across each resistor using the voltmeter and measure the current through the battery using the ammeter. WW W R ( 1 ) V (Volts) 100 0 1500 0 9 9 . 38 122.9 my U 0OOL M 3 25 . 5 0 . 4637 M 5 5 5. 8 0 . 3378 330 0 560 0 1004 -5 0- 97 76 1476 1. 3354 1.5 V Current out of battery = 2 . 679 mv PART B Construct the circuit below using both batteries and the resistors. You must get the instructor's approval that the circuit is correct before continuing. Measure the voltage across each resistor using the voltmeter. EMF2 330 0 R (2) V (Volts) 0 099 S U OOL 0. 2239 U OOOL M 99. 38 M 325. 5 0. 3 690 EMF1 5 5 5.8 0. 8692 1476 1 61 3 6949 1500 0 1004 . 5 - 1 . 2238at near cuide), locate in sing the coordinates on the (1) For Part A, calculate the current across each resistor and the power dissipated in each. Also, calculate the power supplied by the battery. Resistance () Current (A) Power (W) (i) Total Power dissipated in the resistors: (ii) Power supplied by the battery: (2) For Part B, solve for the currents in each resistor using Kirchhoff's rules. Explicitly write down two loop equations and one junction equation and solve for the currents by hand. No matrices. No computers. Just you, the equations, and a calculator to do arithmetic. (3) For Part B, calculate the current across each resistor from your measured data and the percent difference between the values calculated above using Kirchhoff's Laws. Resistance () Current (A) % Difference