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VI. The degradation of iodide by hypochlorous acid relies on a two-step mechanism where the first elementary step is an equilibrium followed by a rate

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VI. The degradation of iodide by hypochlorous acid relies on a two-step mechanism where the first elementary step is an equilibrium followed by a rate determining step as shown below. 1OCl(sq)+H2O(1)k1k2k1HOCl(aq)+OH(aq)fast,Kc=2.981042r(aa)+HOCl(aq)k2HOl(aa)+Cl(aq)slow a. Write the rate laws for each of the elementary step

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