Question
Wanted to get see if my solution is correct. 1) Calculate a 95% and 99% population confidence interval for the following random data set. Note:
Wanted to get see if my solution is correct.
1)Calculate a 95% and 99% population confidence interval for the following random data set. Note: this is a sample. Show your steps including the mean, z-score, sample standard deviation, and standard error that you used. No units for this data.
Data | 12 | 10 | 18 | 16 | 11 | 10 | 9 | 17 | 6 | 13 |
Data | 10 | 20 | 21 | 24 | 18 | 17 | 19 | 12 | 11 | 10 |
Data set 1
n = 10
Mean (x) = 122/10 = 12.2
Standard deviation = 3.82
Confidence interval = 95%
Z score for 95% confidence interval = 1.960
Confidence interval CI =xz
CI =12.2 1.960
CI = 12.2 2.37
Z score for 99% confidence interval = 2.576
Confidence interval CI =xz
CI =12.22.576
CI = 12.2 3.11
95% population confidence interval =12.2 2.37
99%population confidence interval =12.2 3.11
Data set 2
n = 10
Mean (x) = 162/10 = 16.2
Standard deviation = 5.07
Confidence interval = 95%
Z score for 95% confidence interval = 1.960
Confidence interval CI =xz
CI =16.2 1.960
CI = 16.2 3.14
Z score for 99% confidence interval = 2.576
Confidence interval CI =xz
CI =16.2 2.576
CI = 16.2 4.13
95% population confidence interval =16.2 3.14
99%population confidence interval =16.2 4.13
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