We have two solutions of calcium nitrate $Ca(N{O}_3{)}_2$ in $0\mathrm{.}580M$ and $1\mathrm{.}4M$ concentrations. A new solution is prepared by mixing $(Y+120)ml$ from the $1\mathrm{.}4M$ solution and $220ml$ from $0\mathrm{.}589M$ solution. Calculate the concentration of the new solution. solution with a concentration of $0\mathrm{.}375M?$

Y$=40$