We will begin by letting u = sin(69) and dv = e55 d9. Step2 After integration by parts we have / e59 sin(60) d9 = _ 59 e\"sin(66) - Ee/s [e cos(69)d9. Step3 We'll now apply the integration by parts procedure to the new integral [959 cos(60) d9, letting U = cos(69) and dV = e59 d9. W= We) d9 and V = 0 Your answer includes 1 character that can't be graded. Delete your recent changes and use the pad tools to nish your answer. More information q! E After integration by parts we have e5esin 5\" so do: [5 cos( ) 5 (60) X 36/25 x f e59 sin(60) d9