Wed Apr 24 Step 1 To find an antiderivative of f(e) 6 sin 0 + 6 sin @ tan sec we will first re-write the fraction. Factoring out 6 sin in the numerator gives us F(8) 6 sin 0 + 6 sin @ tan sec 6 sin e 1 + tan (0) 1+ (tan (0)) sec 0 Step 2 We know by a trigonometric identity that 1 + tan 0 = sec (0) sec2(0 Step 3 As a result, we have /3 6 sin + 6 sin @ tan 0 sec 0 /3 de = 6 sin (0) 6 sin (9) de. 10 Step 4 An antiderivative of sine is 6(-cos(0)) Step 5 Now, we can say the following. /3 /3 6 sin 0 de = [-6 cos 0] 7/3 0 = (-6 cos ) - 7) - (-6 cos 0) COS II Submit Skip (you cannot come back) - (-6) cos (0)