What average club speed would double the average force?

(A) Find the impulse delivered to the ball. The problem is essentially one I = Ap = Pf - P; = (5.0 x 10-2 kg)(44 m/s) - 0 dimensional. Note that v; = 0, and = +2.2 kg . m/s calculate the change in momentum, which equals the impulse. (B) Estimate the duration of the collision and the average force acting on the ball. Estimate the time interval of the At = Ax _ 2.0 x 10 2 m = 9.1 x 10 4s collision, At, using the approximate av 22 m/s displacement (radius of the ball) and its average speed (half the maximum speed). Estimate the average force. Ap _ 2.2 kg . m/s_ 4 = +2.4 x 103 N 9.1 x 10- 4 s LEARN MORE REMARKS This estimate shows just how large such contact forces can be. A good golfer achieves maximum momentum transfer by shifting weight from the back foot to the front foot, transmitting the body's momentum through the shaft and head of the club. This timing, involving a short movement of the hips, is more effective than a shot powered exclusively by the arms and shoulders. Following through with the swing ensures that the motion isn't slowed at the critical instant of impact. QUESTION What average club speed would double the average force? X Suppose you multiplied the expression for the velocity of the ball symbolically by k. How would that affect