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What happens when the following code is compiled and executed? double d = p.p - 4 g; if (d = 0.0 && Math.sqrt (d) -

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What happens when the following code is compiled and executed? double d = p.p - 4 g; if (d = 0.0 && Math.sqrt (d) - p > 0.0) System.out.println("Has a positive root"); always compiles and runs correctly b syntax error run-time exception when and only when d

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