What is the concentration of $C{H}_{3}N{H}_{3}Cl$ initially produced when $25\mathrm{.}0mL$ of $0\mathrm{.}10MC{H}_{3}N{H}_2$ are reacted with $15\mathrm{.}0mL$ of $0\mathrm{.}15MHCl?$

The acid$-$base reaction that occurs is

$C{H}_{3}N{H}_2(aq)+HCl(aq)longrightarrowC{H}_{3}N{H}_{3}Cl(aq)$

$0\mathrm{.}056M$

$0\mathrm{.}15M$

$0\mathrm{.}125M$

$0\mathrm{.}10M$