When $500\mathrm{.}0g$ of water is decomposed by electrolysis and the yield of hydrogen is only $75\mathrm{.}3\%,$ how much hydrogen chloride can be made if the yield of hydrogen chloride in the second reaction is $69\mathrm{.}8\%?$ Oxygen and chlorine are in excess.

$2H_{2}O2H_2+O_2,75\mathrm{.}3\%$ yield

$H_2+C{l}_{2}2HCl,69\mathrm{.}8\%$ yield