Where H = X = 60 (integer division, of course) and M = X mod 60. You don't have to worry about correct pluralization; i.e., you must print 1 minutes" or *1 hours" if that is the case. The duration of the nap is calculated by the difference between the ending time and the beginning time. That is, if an appointment ends at 14:00 and the next one starts at 14:47, then you have 14:47 - 14:00 - 47 minutes of possible napping. If there is more than one longest nap with the same duration, print the earliest one. You can assume the professor won't be busy all day, so there is always time for at least one possible nap. Sample Input 4 10:00 12:00 Lectures 12:00 13:00 Lunch, like always. 13:00 15:00 Boring lectures... 15:30 17:45 Reading 4 10:00 12:00 Lectures 12:00 13:00 Lunch, just lunch. 13:00 15:00 Lectures, lectures... oh, no! 16:45 17:45 Reading (to be or not to be?) 4 10:00 12:00 Lectures, as everyday. 12:00 13:00 Lunch, again!!! 13:00 15:00 Lectures, more lectures! 15:30 17:15 Reading (I love reading, but should I schedule it?) 1 12:00 13:00 1 love lunch! Have you ever noticed it? :) Sample Output Day #1: the longest nap starts at 15:00 and will last for 30 minutes. Day #2: the longest nap starts at 15:00 and will last for 1 hours and 45 minutes. Day #3: the longest nap starts at 17:15 and will last for 45 minutes. Day #4: the longest nap starts at 13:00 and will last for 5 hours and 0 minutes. Data Structure | Project1 Professors lead very busy lives with full schedules of work and appointments. Professor P likes to nap during the day, but his schedule is so busy that he doesn't have many chances to do so. He really wants to take one nap every day, however. Naturally, he wants to take the longest nap possible given his schedule. Write a program to help him with the task. Input The input consists of an arbitrary number of test cases, where each test case represents one day. The first line of each case contains a positive integer s