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why option 1 is incorrect Suppose we have a function defined in the scipy module as follows (note this is only a screenshot of part
why option 1 is incorrect
Suppose we have a function defined in the scipy module as follows (note this is only a screenshot of part of the function documentation, but it's sufficient to answer the question) scipy.integrate.quad \# scipy.integrate.quad(func, a, b, args=(), full_output =0, epsabs=1.49e-08, epsrel=1.49e-08, limit=50, points=None, weight=None, wvar=None, wopts=None, [source] Compute a definite integral. Integrate func from a to b (possibly infinite interval) using a technique from the Fortran library QUADPACK. Parameters: func: \{function, scipy.LowLevelCallable\} A Python function or method to integrate. If func takes many arguments, it is integrated along the axis corresponding to the first argument. If the user desires improved integration performance, then f may be a scipy. Low Level Callable with one of the signatures: you may also click here Gfor the whole documentation if needed. To import this function, you may use and in your jupyter notebook, a function named is ready use. Assume now the function is already imported correctly as Which of the following is using the correct syntax to call the function, i.e. no error message will be displayed? (don't worry about the actual result mathematically) integrate.quad (func = lambda x:x2,0,1, full_output =1, epsabs =1e6) integrate. quad (x2,a=0,b=1) integrate. quad (lambda x:x2,0,b=1, epsabs =1e6) integrate. quad (x.2,0,1)Step by Step Solution
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