will award most points to best answer , must be able to use with oracle. here is code for the question

drop table workon; drop table employee; drop table project; drop table division; create table division (did integer, dname varchar (25), managerID integer, constraint division_did_pk primary key (did) ); create table employee (empID integer, name varchar(30), salary float, did integer, constraint employee_empid_pk primary key (empid), constraint employee_did_fk foreign key (did) references division(did) ); create table project (pid integer, pname varchar(25), budget float, did integer, constraint project_pid_pk primary key (pid), constraint project_did_fk foreign key (did) references division(did) ); create table workon (pid integer references project(pid), empID integer references employee(empID), hours integer, constraint workon_pk primary key (pid, empID) ); /* loading the data into the database */ insert into division values (1,'engineering', 2); insert into division values (2,'marketing', 1); insert into division values (3,'human resource', 3); insert into division values (4,'Research and development', 5); insert into division values (5,'accounting', 4); insert into project values (1, 'DB development', 8000, 2); insert into project values (2, 'network development', 6000, 2); insert into project values (3, 'Web development', 5000, 3); insert into project values (4, 'Wireless development', 5000, 1); insert into project values (5, 'security system', 6000, 4); insert into project values (6, 'system development', 7000, 1); insert into employee values (1,'kevin', 32000,2); insert into employee values (2,'joan', 42000,1); insert into employee values (3,'brian', 37000,3); insert into employee values (4,'larry', 82000,5); insert into employee values (5,'harry', 92000,4); insert into employee values (6,'peter', 45000,2); insert into employee values (7,'peter', 68000,3); insert into employee values (8,'smith', 39000,4); insert into employee values (9,'chen', 71000,1); insert into employee values (10,'kim', 46000,5); insert into employee values (11,'smith', 46000,1); insert into workon values (3,1,30); insert into workon values (2,3,40); insert into workon values (5,4,30); insert into workon values (6,6,60); insert into workon values (4,3,70); insert into workon values (2,4,45); insert into workon values (5,3,90); insert into workon values (3,3,100); insert into workon values (6,8,30); insert into workon values (4,4,30); insert into workon values (5,8,30); insert into workon values (6,7,30); insert into workon values (6,9,40); insert into workon values (5,9,50); insert into workon values (4,6,45); insert into workon values (2,7,30); insert into workon values (2,8,30); insert into workon values (2,9,30); insert into workon values (1,9,30); insert into workon values (1,8,30); insert into workon values (1,7,30); insert into workon values (1,5,30); insert into workon values (1,6,30); insert into workon values (2,6,30); 

1 List the name of employee and total hours he works on the project (use outer join so that employees who don't work on project will be also listed with zero project count , refer to chapter 2)

2 List the total number of projects whose budget is above the average project budget.

3. List the name of project that is managed/sponsored by chen's division

4 List the name of project that has more than two employees working on it

5. List the name of the division that has more than 2 employees who work on project.

6. List the name of the managers who do not work on any projects. (note, use subquery, the manager is the employee whose ID is in division table)

7. List the name of project and the name of its sponsoring division that has more budget average budget of projects.

8. List the name(s) of employees who is/are working on some project(s) but not on the project "Web development"