The empirical formula for plastic is C₆H₁₀O₅. A chemist wants to study how the material decomposes when exposed to ultraviolet light and decides it would be easier if he used the deuterated form of the material, C₆D₁₀O₅, where each hydrogen atom, H, with an atomic mass of 1.00 g/mole has been replaced by the deuterium isotope of hydrogen, D, that has a mass of 2.00 g/mole. Explain.