with mm $=114$ gg $$and c$=1090$J$/($kg$$K$)$c$=1090$J$/($kg$$K$),$ is initially at room temperature $(24\mathrm{.}0$C$$C$).$ Coffee and cream will be added to the cup. Assume that no heat is exchanged with the surroundings, and that the specific heat of coffee and cream are the same as the specific heat of water, c $=4186$ J$/($kg$$K$)$J$/($kg$$K$)$

In both of the two situations, the same amount of coffee $230$ gg at the same initial temperature $79\mathrm{.}0$C$$C is added to the cup.

But different amounts of cream of $5\mathrm{.}0$C$$C is added to the cup.

note: J$/($kg$$K$)$J$/($kg$$K$)=$J$/($kg$$C$)$

$$ After $230$ gg of $79\mathrm{.}0$C$$C coffee and unknown amount of $5\mathrm{.}0$C$$C cream are added to the cup, the equilibrium temperature of the system $($Coffee $+$ Cream $+$ Cup$)$ is measured to be $59\mathrm{.}0$C$$C$.$

Hint $2$for Part A$.$ How much heat was released by coffee? Each heat is POSITIVE.