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Without the use of import Write a function called take part of list in python that works with single linked lists that will remove and
Without the use of import Write a function called take part of list in python that works with single linked lists that will remove and return a specific part of a linked list based on a given requirement
class Node: """A node for linked lists in a Queue.""" def __init__(self: 'Node', priority: int) -> None: self._next = None self._priority = priority def get_next(self: 'Node') -> 'Node': return self._next def set_next(self: 'Node', next: 'Node') -> None: self._next = next def get_item(self: 'Node') -> object: return self._item def set_item(self: 'Node', item: object) -> None: self._item = item def get_priority(self: 'Node') -> int: return self._priority def set_priority(self: 'Node', priority: int) -> None: self._priority = priority
class SLL(): def __init__(self): self._head = None
def take_part_of_list(self,pri)
so if the linked list was
dog = SLL()
dog = (10)->(8)->(7)->(6)->(5)
dog.take_part_of_list(7)
that would return(7)->(6)->(5)
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