WOLFRAM Player a Player File Edit Window elp Untitled-18 i Hnd 4 r l 0 vl_ . . . . . 50 100 150 200 250 300 350 Measule Value The number of measures is 2207. The sum of all measures is 4408234. The sum of all squared measures is 9337317352. The best measure of central tendency for a uni modal , symmetrical distribution is the sample mean. 49.95 66.65 83.35 100. 116. 133. 150. 166. 183. 200. 216. 233. 250. 267. 283. 300. 317. 333. 350. 05 75 45 15 85 55 25 95 65 35 05 75 45 15 85 55 Category Boundary Number of measures below the bounda ry 0 7 21 50 103 204 340 553 909 1102 1400 1671 1862 2018 2118 2166 2188 2202 2207 Percentile Value of the category bounda ry 0 0.3171700 0.9515200 2.265520 4.666970 9.243320 15.40553 25.05664 36.65609 49.93203 63.43453 75.71364 84.36792 91.43634 95.96738 98.14227 99.13910 99.77345 100.0000 3w v Q _ , 0 Module 2 Notebook for student 1008090664 96% v WOLFRAM Player i MM] 4 > l 100 7 1 80 r 3 . 2 g 60 7 2 a E i5 g 40 7 3 20 7 3 0 . 50 100 150 200 250 300 350 Measure Value 0 Determine the percentile value of the measure 151.9 (to two digits to the right of the decimal point). You are wrong .I The percentile value of the measure 1519 is not "6.16 \". Hint: The percentile value of a measure is the percentage of measures less than that value. Examine the cumulative frequency plot. Find the real limit that is just below the measure (call this limit X L) and the real limit that is just above that measure (call this limit X y). Find the percentile values corresponding to these two limits (YL and Y1], respectively). Then linearly interpolate between the two points (XL,YL) and (X MY\") to nd the percentile value Y corresponding to the measure X in question. When interpolating use full measurement precision. Then round of your answer to two decimal places. The current number of errors is 25. Cancel m The current number of errors is 26. j The current number of errors is 27