Write a Python recursive function called 'invertedImage' that accepts 2 characters 'top' and 'bottom', an integer 'n' representing rows, and an integer 's' representing spaces. This function displays an image of 'n' number of rows of the top character starting with 'n' characters on the first row, n - 1 on the second row, etc. Each row is indented using spaces starting with 's' spaces on the first row and the number of spaces increases by 1 for each subsequent row. After the image using the top character is displayed, another image using the bottom character is displayed starting with 1 character and proceeding to 'n' characters with each row indented using n - 1 spaces, then n - 2, etc. You may assume that the rows will be a positive number greater than 1 and that spaces will always be sent in a value of 0. For example, invertedImage('*', '#', 6, 0) will display: ****** ***** **** *** ** * # ## ### #### ##### ###### For example, invertedImage('?', '8', 4, 0) will display: ???? ??? ?? ? 8 88 888 8888 The function prototype MUST be: def invertedImage(top, bottom, n, s) : 

Using the main below:

import math import random import string import collections import datetime import re import time import copy # YOUR CODE BELOW...  def writeVertical(n) : # your code here... # end def def digitalSum(n) : # your code here... # end def def exponents(a, b) : # your code here... # end def def invertedImage(top, bottom, n, s) : # your code here... # end def  def main( ) : writeVertical(98312) print("===") writeVertical(0) print("===") writeVertical(-123456789) print("===") print(digitalSum(1234)) print("===") print(exponents(3, -4)) print("===") print(exponents(16, 0)) print("===") print(exponents(0, 9)) print("===") print(exponents(-18, 7)) print("===") print(exponents(12, 12)) print("===") invertedImage('*', '#', 6, 0) print("===") invertedImage('@', '^', 18, 0) # end main( ) if __name__ == "__main__" : main( )