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Write a recursive method in Java called sumTo that accepts an Integer parameter and returns the sum of the first n reciprocals as a double.
Write a recursive method in Java called sumTo that accepts an Integer parameter and returns the sum of the first n reciprocals as a double.
In other words:
sumTo(n) returns: 1 + 1/2 + 1/3 + 1/4 + ... + 1/n
Your answer should be rounded to 2 decimal places. The following code will help:
Math.round(result * 100.0) / 100.0;
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