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Write a recursive method in Java called sumTo that accepts an Integer parameter and returns the sum of the first n reciprocals as a double.

Write a recursive method in Java called sumTo that accepts an Integer parameter and returns the sum of the first n reciprocals as a double.

In other words:

sumTo(n) returns: 1 + 1/2 + 1/3 + 1/4 + ... + 1/n

Your answer should be rounded to 2 decimal places. The following code will help:

 Math.round(result * 100.0) / 100.0;

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