$x^{3}y-2x^2+y^4=8$

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Find $\frac{dy}{dx}.$

Choose $1$ answer:

$(4)\frac{x^3+4y^3}{4x-3x^{2}y}$

$($B$)-\frac{4x}{3x^2+4y^3}$

$($C$)\frac{4x-3x^{2}y}{x^3+4y^3}$

$($D$)\frac{4x}{3x^2+4y^3}$