x=0\ y=6\ y=7\ y=8

\ (b) Consider the IVP

d(y)/(d)x=x(y-7)^(2)-5,y(0)=y_(0)

, where

y_(0)

. Can a solution

y(x)->\\\\infty

as

x->\\\\infty

? Based on the information In part (a), discuss.\

y(x)

can approach

\\\\infty

as

x

approaches

\\\\infty

.\

y(x)

cannot approach

\\\\infty

as

x

approaches

\\\\infty

.

x=0y=6y=7y=8 (b) Consider the IVP dy/dx=x(y7)25,y(0)=y0, where y0