You are given a list of lists. Each member is a list of combination of X$,$Y$,$Z$.$ This is generated

randomly from this code:

$1$ data $=[$X$,$Y$,$Z$]$

$2$ d$\_=[]$

$3$ for $\_$ in range$($rn$.$randint $(4,10))$:

$4$ d$\_+=[[$rn$.$choice$($data$),$rn$.$choice$($data$),$rn$.$choice$($data$)]]$

$5$ print$($d$\_)$

One run gives:

$1[[$Y$,$Z$,$Y$],[$X$,$X$,$Z$],[$Y$,$Z$,$Y$],[$X$,$X$,$Z$],[$

$$Y$,$X$,$Z$],[$Z$,$Y$,$X$],[$Z$,$X$,$Y$]]$

You will implement the function cnt$\_$harmonic$($lst$)$ that returns a dictionary with counts of X$,$Y$,$Z

where:

$$If there is a majority of X$,$Y$,$ or Z$,$ then that letter gets a single vote.

$$If there is no majority, i$.$e$.,$ the list is some permutation of $[$Z$,$X$,$Y$],$ then no vote is

recorded.

While you could determine the maximum count of the letters using many different approaches,

the Python dictionary has a convenient way to find the key whose value is maximal. It uses the

function max and two parameters as shown in this session:

$1>>>$ x $=\{1$:$3,2$:$1,3$:$1\}$

$2>>>$ max$($x$,$key$=$x$.$get$)$

$31$

$4>>>$ x $=\{1$:$1,2$:$1,3$:$3\}$

$5>>>$ max$($x$,$key$=$x$.$get$)$

$63$

This is one caveat. When no maximum exists, it simply returns one of the keys are random:

$1>>>$ x $=\{1$:$1,2$:$1,3$:$1\}$

$2>>>$ max$($x$,$key$=$x$.$get$)$

$31$

But you can programmatically deal with this. While there isn$$t any requirement to use this ap$-$

proach, it does make the solution much simpler. Here$$s a run:

$1$ data $=[$X$,$Y$,$Z$]$

$2$ d$\_=[]$

$3$ for $\_$ in range$($rn$.$randint $(4,10))$:

$4$ d$\_+=[[$rn$.$choice$($data$),$rn$.$choice$($data$),$rn$.$choice$($data$)]]$

$5$ print$($d$\_)$

$6$ print$($cnt$\_$harmonic$($d$\_))$

producing

$1[[$X$,$Z$,$X$],[$Y$,$Z$,$X$],[$Z$,$X$,$Y$],[$X$,$Z$,$Y$],[$

$$Y$,$Z$,$X$],[$Y$,$Z$,$X$],[$Y$,$Z$,$X$],[$X$,$Y$,$Z$],$

$[$Z$,$X$,$X$],[$Y$,$Y$,$Y$]]$

$2\{$X$$: $2,$Y$$: $1,$Z$$: $0\}$

Requirements

$1.$ We only use letters X$,$Y$,$Z$.$

$2.$ You are allowed to use max$()$ and count$().$

def cnt$\_$harmonic$($lst$)$: