You are given the following memory and its contents in the table below for a word aligned Little Endian 16 bit processor. Main memory

Question: What is the contents of the indirect address 6(0x04) which we would write as ((6+0x04))? Remember not to confuse decimal and hexadecimal values. All hex numbers are preceded by 0x. Otherwise, it is decimal. Data should be a 2 byte hex number in the proper order.

Address OISE Data Data Data Data Data Data Data Data Data Data 1 Data Data Data 8 Data 9 0 0 00XD Cx00 Cx 10 ) TOXO OTXO Data 5 OxDD OXO OxDD HEXO IIXO Data 7 Ox10 OxDD Ox81 (x00 Cx 10 Cx20 Cx 12 Ox00 Ox00 Ox00 00xp 00xp 00xD TOXO TOXO TOXO Ox00 Ox00 Ox00 OxOS 0x30 Oxl O0 Ox00 CxFF Ox03 Oxlc 003 Ox2 0x2F Ox02 00xp OFF 0x30 00xp DOXD Address OISE Data Data Data Data Data Data Data Data Data Data 1 Data Data Data 8 Data 9 0 0 00XD Cx00 Cx 10 ) TOXO OTXO Data 5 OxDD OXO OxDD HEXO IIXO Data 7 Ox10 OxDD Ox81 (x00 Cx 10 Cx20 Cx 12 Ox00 Ox00 Ox00 00xp 00xp 00xD TOXO TOXO TOXO Ox00 Ox00 Ox00 OxOS 0x30 Oxl O0 Ox00 CxFF Ox03 Oxlc 003 Ox2 0x2F Ox02 00xp OFF 0x30 00xp DOXD