You have $180$mL of a dink of water @ $20C$ to which you add one ice cube of $30\mathrm{.}5mL$ volume @ $-18C.$ Assuming no heat exchange with environment, at what temp will your drink be after equilibrium is reached?

$C_{\text{s}\text{o}\text{l}}=2\mathrm{.}09\frac{J}{gxK}$

$P_{\text{s}\text{o}\text{l}}=0\mathrm{.}917\frac{g}{c{m}^3}$

$H_{\text{l}\text{e}\text{u}\text{s}\text{s}}^{}=6\mathrm{.}02k\frac{J}{\text{m}\text{o}\text{l}}$

$C_{1iq}=4\mathrm{.}18\frac{J}{gxk}$

$P_{H_9}=0\mathrm{.}9937\frac{g}{c{m}^3}$

$M=18\mathrm{.}02\frac{g}{\text{m}\text{o}\text{l}}$

A$)7\mathrm{.}499C$

C$)6\mathrm{.}09C$

E$)5\mathrm{.}27C$

B$)7\mathrm{.}50C$

D$)6\mathrm{.}49C$