You have been asked by a small company to divide an address block over four departments (management, HR, accounting, and sales). Divide the given IP address block (check below) with minimal wastage of addresses. Check the following table for the number of addresses required for each department; determine the best subblocks for each department, then fill out the table's remaining fields.

Required information about each subnetwork:

1. Subnetwork address
2. Mask
3. First IP address (use binary calculation)
4. Last IP address (use binary calculation)
5. Address block size (use binary calculation)
6. Wasted addresses (block size required addresses)

The address block is 10.x.y.0/24, where x and y are the last four digits from your Student ID. Therefore, if your St. ID ends with 1740 then x = 17 and y = 40, and the address is 10.17.40.0/24.

Use the binary calculation method to find out the first and last addresses and the block size. Show your entire calculations

Before solving the problem, remember the following points:

- Solve the problem with minimal wastage of addresses.

- Start with bigger size block going to the smallest in size.

- If the requested number of IP addresses for a subnetwork is 15, there are two special types of addresses will be always reserved for other purposes and cant be given to ordinary hosts.

- if the subnet mask of our subnet is 255.255.248.0 in binary calculation it is: 11111111 11111111 11111000 00000000 which is /21

- Host bits = Log2(Number-of-hosts)

Dept. Req. addr. Subnetwork address Mask 1st IP Last IP Block size wasted Mgmt. 5 HR 20 Accounting 10 Sales 33