You have developed a new way to measure the internal resistance of a battery. The circuit you have created is shown, with a battery (EMF and internal resistance r in the red box), a constant external resistor R1 = 15.4 0, and a variable resistor R2. R2 has a resistance you can change over a wide range of values. R1 is used to avoid damaging the battery due to high currents. In this circuit, you measure the voltage over R2, AV2. For one battery, you find the voltage AV2 approaches a constant value, AVmax = 14.9 V when R2 becomes very much larger than R1 (and the internal resistance r). You then reduce the resistance of R2 and when R2 = 23.3 0, the voltage is reduced to half the maximum, AV2 = 1/2 AV max. What is the internal resistance of the battery? Give your answer in Ohms to at least three significant digits to avoid being counted off due to rounding. 6.061 V R 1 r EMF