Verify by direct substitution in the Hamiltonian (11.2.4) that the definition of A(vector)k given in (11.2.6) will
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Verify by direct substitution in the Hamiltonian (11.2.4) that the definition of A(vector)k given in (11.2.6) will eliminate the off-diagonal terms.
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For the sake of brevity we will use Uk i0 1 and V Azeio 1A V 1121 Then for the four operators appear...View the full answer
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