10.127 Null standard error for matched pairs Under the null hypothesis H0: p1 = p2 of equal population proportions, the standard error for the difference in the two sample proportions mentioned in the previous exercise reduces to se0: = 31b + c2 >n2, where b and c are the off-diagonal elements and n is the number of subjects.

a. Show that the null standard error se0 equals 0.010 for the contingency table in Table 10.18.

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b. Compute the value of the test statistic estimate - null value (1-2) - 0 - and Z seo seo b-c verify that it equals - The P-value in the com- b + c puter output of Table 10.19 refers to this test statistic.