An ideal signal voltage source is given by (v_{s}=5 sin (5000 t)(mathrm{mV})). The peak current that can
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An ideal signal voltage source is given by \(v_{s}=5 \sin (5000 t)(\mathrm{mV})\). The peak current that can be supplied by this source is \(0.2 \mu \mathrm{A}\). The desired output voltage across a \(10 \mathrm{k} \Omega\) load resistor is \(v_{o}=100 \sin (5000 t)(\mathrm{mV})\). Design a one-transistor common-emitter amplifier to meet this specification. Use standard resistor values and specify the required value of \(\beta\).
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Related Book For
Microelectronics Circuit Analysis And Design
ISBN: 9780071289474
4th Edition
Authors: Donald A. Neamen
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