The current through a 2-mH inductor is iLt = 4 sin 1000t + 1 sin 3000t A
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The current through a 2-mH inductor is iLðtÞ = 4 sin 1000t + 1 sin 3000t A as shown in Figure 6–12(a). Find the resulting inductor voltage.
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Related Book For 
The Analysis And Design Of Linear Circuits
ISBN: 9781119235385
8th Edition
Authors: Roland E. Thomas, Albert J. Rosa, Gregory J. Toussaint
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