(1 + r)n +HnSn =c(n, Sn). Since H0n and Hn are Fn1-measurable, they are functions of S1,...

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(1 + r)n +HnSn =c(n, Sn).

Since H0n and Hn are Fn−1-measurable, they are functions of S1, . . . , Sn−1 only and, since Sn is equal to Sn−1d or Sn−1u, the previous equality implies H0n

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