According to special relativity, the speed of light should be the same as seen by two observers
Question:
According to special relativity, the speed of light should be the same as seen by two observers moving at different relative velocities. In Newtonian physics, an observer (2) moving at a velocity v in the x-direction relative to an observer (1) labels the x-coordinate of an event by x2 = x1 − vt, where x1 is the coordinate given by the first observer, and both observers use the same time coordinate. Show that with this change of coordinates, the velocity of light traveling in the x-direction is different for the two observers. If a stationary observer sees light passing by at 3×108 m/s, and a second observer is in a rocket ship passing in the same direction at 108 m/s, at what speed would the second observer see the light wave moving if the Newtonian transformation were correct?
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