A 0.5-mm-diameter fiber, 1 cm in length, made from boron nitride is placed in a 120- circuit.

A 0.5-mm-diameter fiber, 1 cm in length, made from boron nitride is placed in a 120-Ω circuit. Using Table 19-1, calculate

(a) The current flowing in the circuit; and
(b) The number of electrons passing through the boron nitride fiber per second.
(c) What would the current and number of electrons be if the fiber were made from magnesium instead of boron nitride?

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Material Superconductors Hg, Nb3Sn YBa₂Cu3O7-x MgB₂ Metals Alkali metals Na K Alkali earth metals Mg Ca Group 3B metals Al Ga Transition metals Fe Ni Group 1B metals Cu Ag Au Conductivity (ohm ¹. cm ¹) Infinite (under certain conditions such as low temperatures) 2.13 X 105 1.64 x 105 2.25 X 105 3.16 x 105 3.77 X 105 0.66 x 105 1.00 x 105 1.46 x 105 5.98 x 105 6.80 x 105 4.26 X 105 Material Semiconductors Group 4B elements Si Ge Compound semiconductors GaAs AIAS Sic Ionic Conductors Polyethylene Polytetrafluoroethylene Polystyrene Epoxy Ceramics Alumina (Al₂O3) Silicate glasses Conductivity (ohm ¹. cm ¹) Indium tin oxide (ITO) Yttria-stabilized zirconia (YSZ) Insulators, Linear, and Nonlinear Dielectrics Polymers Boron nitride (BN) Barium titanate (BaTiO3) C (diamond) 4 x 10-6 0.02 2.5 × 10-9 0.1 10-10 -104 <1014 10-15 10-18 10-17 to 10-19 10-12 to 10-17 10-14 10-17 10-13 10-14 <10-18