=+6. Prove that there are 8!8 k=0 (1)k k! ways of placing eight rooks on a chessboard

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=+6. Prove that there are 8!8 k=0

(−1)k k! ways of placing eight rooks on a chessboard so that none can take another and none stands on a white diagonal square [59]. (Hint: Think of the rook positions as a random permutation π, and let Ai be the event {π(i) = i}.)

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Applied Probability

ISBN: 9781441971647

2nd Edition

Authors: Kenneth Lange

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Question Posted: Nov 01, 2024 02:00 AM

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=+6. Prove that there are 8!8 k=0 (1)k k! ways of placing eight rooks on a chessboard

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Applied Probability

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