Applying the proposition to Example 2.23 yields E[X2] = 02 (0.2) + (12 )(0.5) + (22 )(0.3)
Question:
Applying the proposition to Example 2.23 yields E[X2] = 02
(0.2) + (12
)(0.5) + (22
)(0.3) = 1.7 which, of course, checks with the result derived in Example 2.23.
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