Applying the proposition to Example 2.23 yields E[X2] = 02 (0.2) + (12 )(0.5) + (22 )(0.3)

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Applying the proposition to Example 2.23 yields E[X2] = 02

(0.2) + (12

)(0.5) + (22

)(0.3) = 1.7 which, of course, checks with the result derived in Example 2.23.

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Introduction To Probability Models

ISBN: 9780123756862

10th Edition

Authors: Sheldon M Ross

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Question Posted: Sep 16, 2024 03:01 AM

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Applying the proposition to Example 2.23 yields E[X2] = 02 (0.2) + (12 )(0.5) + (22 )(0.3) = 1.7 which, of course, checks with the result derived in Example 2.23.
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Applying the proposition to Example 2.23 yields E[X2] = 02 (0.2) + (12 )(0.5) + (22 )(0.3)

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Introduction To Probability Models

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