Consider the bridge structure with identical component probabilities. That is, take pi to equal p for all

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Consider the bridge structure with identical component probabilities.

That is, take pi to equal p for all i. LettingA1 = {1, 4},A2 = {1, 3, 5},A3 =

{2, 5}, and A4 = {2, 3, 4} denote the minimal path sets, we have P(E1) = P(E3) = p2, P(E2) = P(E4) = p3 Also, because exactly five of the six =

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unions of Ai and Aj contain four components (the exception being A2 ∪ A4, which contains all five components), we have P(E1E2) = P(E1E3) = P(E1E4) = P(E2E3) = P(E3E4) = p4, P(E2E4) = p5

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