For the particle in a box, we chose k np L with n 1, 2, 3, c to fit the boundary condition that 0 at x L However, n 0, 1, 2, 3, c also satisfy that boundary condition Why didnt we also choose those values of n ...

n 0 given k 0 and from Eq4029 x 0 This wave function is a triv ...

For the particle in a box, we chose k = np/L with n = 1, 2, 3,

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For the particle in a box, we chose k = np/L with n = 1, 2, 3, c to fit the boundary condition that ψ = 0 at x = L. However, n = 0, -1, -2, -3, c also satisfy that boundary condition. Why didn’t we also choose those values of n?

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University Physics with Modern Physics

ISBN: 978-0133977981

14th edition

Authors: Hugh D. Young, Roger A. Freedman

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Question Posted: Nov 01, 2018 12:03 PM

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For the particle in a box, we chose k = np/L with n = 1, 2, 3,

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n 0 given k 0 and from Eq4029 x 0 This wave function is a triv...View the full answer

University Physics with Modern Physics

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