Question: How much energy is imparted to one cell during one days treatment? Assume that the specific gravity of the tumor is 1 and that 1

How much energy is imparted to one cell during one day’s treatment? Assume that the specific gravity of the tumor is 1 and that 1 J = 6 × 1018 eV.

(a) 120 keV;

(b) 12 MeV;

(c) 120 MeV;

(d) 120 × 103 MeV.


Malignant tumors are commonly treated with targeted x-ray radiation therapy. To generate these medical x rays, a linear accelerator directs a highenergy beam of electrons toward a metal target—typically tungsten. As they near the tungsten nuclei, the electrons are deflected and accelerated, emitting high-energy photons via bremsstrahlung. The resulting x rays are collimated into a beam that is directed at the tumor. The photons can deposit energy in the tumor through Compton and photoelectric interactions. A typical tumor has 108 cells/cm3, and in a full treatment, 4-MeV photons may produce a dose of 70 Gy in 35 fractional exposures on different days. The gray (Gy) is a measure of the absorbed energy dose of radiation per unit mass of tissue: 1 Gy = 1 J/kg.

Step by Step Solution

3.41 Rating (176 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

IDENTIFY and SET UP The specific gravity of the tumor is 1 so it has the same ... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related University Physics Questions!