Find the solution of the initial value problem y'-2/t(y)= 2t^2e^(2(t-1), t>0, y(1)=3
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y'-2/t(y)= 2t^2e^(2(t-1), t>0, y(1)=3
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dydt 2ty 2t 2 e 2t1 If we compare the above equation with the sta...View the full answer
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Find the solution of the initial value problem y'-2/t(y)= 2t^2e^(2(t-1), t>0, y(1)=3
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