Question: The position function x(r) of a particle moving along an x axis is x = 4.0 6.0 t 2 , with x in meters

The position function x(r) of a particle moving along an x axis is x = 4.0 – 6.0t2, with x in meters and t in seconds.

(a) At what time and 

(b) Where does the particle (momentarily) stop? At what 

(c) Negative time and 

(d) Positive time does the particle pass through the origin? 

(e) Graph x versus t for the range – 5s to + 5 s. 

(f) To shift the curve rightward on the graph, should we include the term + 20t or the term – 20t in x(t) ?

(g) Does that inclusion increase or decrease the value of x at which the particle momentarily stops?

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