Ti 3+ is to be generated in 0.10 M HClO 4 solution for coulometric reduction of azobenzene.

Question:

Ti3+ is to be generated in 0.10 M HClO4 solution for coulometric reduction of azobenzene.

TiO?+ + 2H+ + e = Ti³+ + H,0 E° = 0.100 V 4T1³* + C,H;N=NC,H; + 4H,0 → 2C,H;NH, + 4TIO²* + 4H* Azobenzene Aniline

At the counter electrode, water is oxidized, and O2 is liberated at a pressure of 0.20 bar. Both electrodes are made of smooth Pt, and each has a total surface area of 1.00 cm2. The rate of reduction of the azobenzene is 25.9 nmol/s, and the resistance of the solution between the generator electrodes is 52.4 Ω.

(a) Calculate the current density (A/m2) at the electrode surface. Use Table 16-1 to estimate the overpotential for O2 liberation.

(b)Calculate the cathode potential (versus S.H.E.) assuming that [TiO2+] surface [TiO2+]bulk 0.050 M and [Ti3+]surface 0.10 M.

(c) Calculate the anode potential (versus S.H.E.).

(d) What should the applied voltage be?

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question
Question Posted: