Question: Two thin rods of length L lie along the x-axis, one between x = a/2 and x = a/2 + L and the other between

Two thin rods of length L lie along the x-axis, one between x = a/2 and x = a/2 + L and the other between x = -a/2 and x = -a/2 - L. Each rod has positive charge Q distributed uniformly along its length.
(a) Calculate the electric field produced by the second rod at points along the positive x-axis.
(b) Show that the magnitude of the force that one rod exerts on the other is

(a + L)? Q? In 4me,L

(c) Show that if a » L. the magnitude of this force reduces to F = Q2/4πє0a2 (Hint: Use the expansion in (1 + z) = Z - z2 /2 + z3/3 - ..., valid for |z| « 1. Carry all expansions to at least order L2 / Ia2.) Interpret this result.

(a + L)? Q? In 4me,L"a(a + 2L)

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IDENTIFY To find the electric field due to the second rod divide that rod into infinitesimal segments of length dx calculate the field dE due to each segment and integrate over the length of the rod to find the total field due to the rod Use dF dq to find the force the electric field of the second rod exerts on each infinitesimal segment ... View full answer

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