When 2-chloro-2-methylbutane is treated with a variety of strong bases, the products always seem to contain two isomers (A and B) of formula C5H10. When sodium hydroxide is used as the base, isomer A predominates. When potassium tert-butoxide is used as the base, isomer B predominates. The 1H and 13C NMR spectra of A and B are given below.
(a) Determine the structures of isomers A and B.
(b) Explain why A is the major product when using sodium hydroxide as the base and why B is the major product when using potassium tert-butoxide as the base.

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200 180 160 140 120 100 80 60 40 20 0 3C NMR CDCl OHz 50Hz OHz isomer A 526 5.16 1.7δ 1.6δ 10 0 δ (ppm) 200 180 160 140 120 100 80 40 20 0 CNMR CDCI3 isomer B 10 6 4 0 δ (ppm)