When a mixture of methane and bromine vapor is exposed to light, the following reaction occurs slowly:

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When a mixture of methane and bromine vapor is exposed to light, the following reaction occurs slowly:
CH4(g) + Br2(g) → CH3Br(g) + HBr(g)
Suggest a mechanism for this reaction. (Bromine vapor is deep red; methane is colorless.)
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Chemistry

ISBN: 978-0077274313

10th edition

Authors: Raymond Chang

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