Factor each of the following, noting that the coefficient of the x term is negative while the constant term is positive.

(a) x2 – 13x + 30 With (c ·

d) positive and (c +

d) negative, the two integer factors must both be negative. We can no longer limit ourselves to positive factors for c and d.

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(1) c d = 30 [-1,-30; -2, -15; -3, -10; -5, -6] (2) c+d=-13 (b) x-15x+36 (1) c d = 36 (2) c+d-15 [only 3+(-10)=-13] x 13x+30= (x-3)(x - 10) - [-1,-36;-2,-18; -3, -12; -4, -9; -6, -6] [-3+(-12)=-15] x-15x+36=(x-3)(x - 12)