Consider Example 9.6 with the null hypothesis H0 : P = P0 = 0.50 and the alternative hypothesis H0 : P ? 0.50 The decision rule is pn x - 0.50 10.5011 - 0.502>600 6 -1.96 or pn x - 0.50 10.5011 - 0.502>600 7 1.96 with a sample size of n = 600. What is the probability of Type II error if the actual population proportion is each of the following?

a. P = 0.52

b. P = 0.58

c. P = 0.53

d. P = 0.48

e. P = 0.43 Application Exercises