Suppose the events B1, B2, and B3 are mutually exclusive and complementary events such that P1B12 = .55, P1B22 = .35, and P1B32 = .1. Consider another event A such that P1A2 = .2. If A is independent of B1, B2, and B3, use Bayes’s rule to show that P1B1 0A2 = P1B12 = .55.