The second derivative of y = x 2 is dy 2 /d 2 x = 2. Verify
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The second derivative of y = x2 is dy2/d2x = 2. Verify that Eq. (11) applied to c(t) = (t, t2) yields dy2/d2x = 2. In fact, any parametrization may be used. Check that c(t) = (t3, t6) and c(t) = (tan t, tan2 t) also yield dy2/d2x = 2
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For the parametrization ct t 2 we have so that indeed For ct t t we have so that again and xt ...View the full answer
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