A cell was constructed with two lead electrodes. The electrolyte in one compartment is 1.0 m Pb(NO
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A cell was constructed with two lead electrodes. The electrolyte in one compartment is 1.0 m Pb(NO3)2(aq). In the other compartment, NaI has been added to a Pb(NO3)2 solution until a yellow precipitate forms and the concentration of I– ions is 0.050 mol · L–1. The potential of this cell is +0.155 V at 298 K.
(a) Calculate the concentration of Pb+ ions in the second compartment.
(b) Calculate the solubility product of PbI–.
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a Calculating Pb Concentration in the Second Compartment Write the Nernst equation The cell potentia...View the full answer
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Related Book For 
Chemical Principles The Quest For Insight
ISBN: 9781464183959
7th Edition
Authors: Peter Atkins, Loretta Jones, Leroy Laverman
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