Calculate the (mathrm{pH}) of (6.0 times 10^{-4} mathrm{M} mathrm{NaNO}_{2}).
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Calculate the \(\mathrm{pH}\) of \(6.0 \times 10^{-4} \mathrm{M} \mathrm{NaNO}_{2}\).
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Sodium nitrite NaNO2 is a salt of a weak base NO2 and a strong acid HNO2 Therefore it wont directly ...View the full answer
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